Question

Resistance of a conductivity cell filled with 0.1 mol L KCl solution is 100 12. If the resistance of the same cell when filled with 0.02 molt KCl solution is 520 12, calculate the conductivity and molar conductivity of 0.02 mol L KCl solution. The conductivity of 0.1 mol KC solution is 1.29 S/m. in diren by the equation:??​

Answer 1

Explanation:

k=Cell constant/ Resistance

=1.29/520 =2.48×10³S cm¹

Molar conductivity ^m=10³×2.48×10³ / 0.02= 1245cm² mol¹