Question

resistance of a conductor of length 1m and cross sectional area of 1mm^2 is 8 ohm.find the specific resistance

Answer 1

Resistance = resistivity x L/A
Resistivity = (RxA) / L
Area = 1 x 10^-6 m^2
Resistivity = (8x 1x10^-6)/1
Resistivity = 8 x10^-6

Answer 2

Answer:

Explanation:

Resistance is proportional to the length of the path over which the current is flowing, but is inversely propotional to the cross-sectional area.

Res = (rho x length)/Area

Resistance = resistivity x L/A  

Resistivity = (RxA) / L

For Resistance =8 ohm

length = 1m

A = (1mm)² =1e-06 m²

rho= 8 x 1e-6 / 1

= .000008 ohm

Therefore, the specific resistance of the conductor is .000008 ohm