Physics, asked by amalbinu6885, 1 year ago

Resistance of a galvanometer is g shunt used at allow 1 of main current through the galvanometer is

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Answered by rishabhbhattacp356lm
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In an ammeter (consisting of a galvanometer and a shunt), 0.5% of the main current passes through the galvanometer. Resistance of the galvanometer coil is G. Calculate the resistance of the shunt in terms of galvanometer resistance, G.

In an ammeter (consisting of a galvanometer and a shunt), 0.5% of the main current passes through the galvanometer. Resistance of the galvanometer coil is G. Calculate the resistance of the shunt in terms of galvanometer resistance, G.

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S= GIg/(I-Ig)

Ig = 5%(I)=I/20

Therefore S = G(I/20)/(I-I/20) S= G/19ohms

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