Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is:
A. 6%
B. ZeroC. 1%
D. 3%
Answers
From Ohms law we know that, V = I x R where, V is the potential difference, I is the current and R is the resistance.
Now acc to the question % error in resistance = %error in V + %error in I
= 0.03 x 100 + 0.03 x 100
= 3 + 3 = 6% (Ans)
The error in the Potential difference is 0.03 and that in the current is 0.03. Now the error in Resistance will be the summation of both which is 0.06.
Therefore %error will be 0.06 x 100% = 6% (Ans) i.e. option A
Answer ⇒ Option (A).
Explanation ⇒
% Error in Voltage = 3 %
% Error in Current = 3 %
∵ Resistance = V/I
We know that whenever the quantities are multiplied or divided the % Error in the final result is the sum of the % error of the quantities.
∴ % Error in Resistance = 3 + 3
= 6 %
Hence, Option (A). is correct.
Hope it helps.