Resistance of a wire is doubled and then what is the change in length and constant area of cross section?
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length increases root 2 times and area decreases root 2 times
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let length be l crossection be a and density be q
we know that
R=ql/a
final
2R=ql/a
so
R/2R=ql(initial)/a/ql(final)/a
l initial /l final =1/2
l final =2* length of wire in initial
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