Question

resistance of filament of a bulb is 100 watt . how much heat is in calories will be produced by it in half an hour if it is connected to 200 volt supply

Answer 1

Heat generated will be equal to $1.72\times 10^5calorie$

Explanation:

Resistance of the bulb filament is 100 ohm ( Note unit of resistance is ohm but here it is given watt)

Bulb is connected with a supply voltage of 200 volt

So potential difference V = 200 Volt

Power of the bulb is given by $P=\frac{V^2}{R}$

$P=\frac{200^2}{100}=400watt$

Time t = half an hour = 30×60 = 1800 sec

Energy is equal to $E=P\times t$

$E=400\times 1800=7.2\times 10^5J$

As 1 J = 0.239 calorie

So $7.2\times 10^5J=0.239\times 7.2\times 10^5=1.72\times 10^5calorie$

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