resistance per metre length of a wire is 10 ohm if the resistivity of the material is 50 into 10 to the power minus 8 ohm metre find the area of cross section of the wire
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R ( resistance ) = 100 ohm
rho ( resistivity ) = 50*10^-8 ohm meter
L = 1m
we know that,
R =( rho * L ) / A
by substituting the above given values we get,
100 = {( 50*10^-8)*(1)} / A
A = {( 50*10^-8)*(1)} / 100
A = 5*10^-9 m^2
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rho ( resistivity ) = 50*10^-8 ohm meter
L = 1m
we know that,
R =( rho * L ) / A
by substituting the above given values we get,
100 = {( 50*10^-8)*(1)} / A
A = {( 50*10^-8)*(1)} / 100
A = 5*10^-9 m^2
Mark as Brailiest if it helps you ✌✌
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