Resistance wire is stretched to new length such that percentage increase is 10%. Find percentage increase in resistance.
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A cylindrical wire is stretched to increase its length by 10% . the percentage increase in the resistance of the wire will be. So, new C.S Area of extended wire A2 = Pi (r1)^2 = 0.91 Pi r^2. So, new value of resistance = R1 = Rho .
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A cylindrical wire is stretched to increase its length by 10% . the percentage increase in the resistance of the wire will be. So, new C.S Area of extended wire A2 = Pi (r1)^2 = 0.91 Pi r^2. So, new value of resistance = R1 = Rho .
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