Question

Resistance wire of length l cross section a is 26 ohm if the wire is drawn how to increase its length by twice the initial length what will be its resistance in the new condition

Answer 1

Answer:

Your answer is 104 ohm

Explanation:

Answer

When length of wire is doubled i.e. 2l

Also it's area of cross section becomes half i.e

2/A

Resistance R= ρl/A

=26Ω

New Resistance ,

R' = ρl' \A'

= ρ(2l)×2/A

=4( ρl) /A

=4(ρl /A)

=4×26

=104Ω