Question

Resistances of 5 Ω, 7 Ω and 8 Ω are connected in series. If a 10 V supply voltage is connected across the arrangement determine the current flowing through and the 7 Ω resistor. Calculate also the power dissipated in the 8 Ω resistor.

Answer 1

Answer:

I think this is the answer

Answer 2

Answer:

Current- 0.5 A

Power dissipated in the 8Ω resistor- 2 Watt

Explanation:

In a series circuit, individual resistors sum to give an equivalent resistance, and the current flowing through each resistor is the same. The total power is the sum of all the power dissipated by each resistor. While the sum of the voltage across the resistors is equal to the voltage supplied.

Step by step calculation

To find the current, we first add the values of resistors to get equivalent resistance.

5Ω+7Ω+8Ω=20Ω

Next, we use I=$\frac{V}{R}$ where,

I-Current (A)

V-Voltage supplied (V)

R- Resistance (Ω)

I=$\frac{10}{20}$

= 0.5 A

The current at 7Ω resistor is 0.5A too.

To find the power dissipated in the 8Ω resistor, we use P=I²R

P=(0.5)²8

= 2 Watt

Conclusion:

The current is 0.5 A and the power dissipated at 8Ω is 2 Watt.