resistances of 5ohms, 6 ohms 50ohms and 60ohm are connected in the Four Arms of the wheatstone bridge. If a cell of EMF 1.5 volt and negligible internal resistance is connected across the bridge, calculate the current in the arms of the wheatstone bridge and the cell.
Answers
Answered by
1
Current I= total EMF/ total resistance
I=1.5/10
=.15ampere
Similar questions