Resistances of three resistors are in the proportion connected in parallel, their effective resistance is 6 Ω. Then connect on.
Answers
Answer:
Explanation:
Total 6 nos. Of 6 ohm resistors are required to get effective resistance of 4 ohms.
Connect 2 set of three resistors of 6 ohms in parallel and connect both set in the series. The effective resistance will be 2 ohms
R = 6/3 + 6/3
R= 2 + 2
R = 4 ohms
Hope it helps you!!!
Given:
Resistances of three resistors are in the proportion connected in parallel, their effective resistance is 6 Ω.
To find:
Resistances of three resistors are in the proportion connected in parallel, their effective resistance is 6 Ω. Then connect on.
Solution:
From given, we have,
Resistances of three resistors are in the proportion connected in parallel, their effective resistance is 6 Ω.
As it's not given that, 3 resistors have different values, so we consider all the 3 resistors have the same value.
The formula for calculating the resistance of resistors connected in parallel, we get,
1/Rp = 1/R1 + 1/R2 + 1/R3
1/Rp = 1/R + 1/R + 1/R
1/Rp = 3/R
Rp = R/3
6 = R/3
R = 18 Ω
Therefore, option (d) 18 Ω is correct.