Resistances R1 = 10 , R2= 6 R3=8 are connected in series. Calculate the total resistance &
current flowing in each resistance, If the potential difference is 12V
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Resistances are R1 = 10 , R2= 6 R3=8 are connected in series.
R1 = 10 ohm
R2 = 6 ohm
R3 = 8 ohm
Total resistance, R = R1 + R2 + R3 = 10+6+8 = 24 ohm
Potential difference = 12 V
Current through circuit = V/R = 12/24 = 0.5A
In series, current through each resistor remains same. So current through each resistor is 0.5 A
R1 = 10 ohm
R2 = 6 ohm
R3 = 8 ohm
Total resistance, R = R1 + R2 + R3 = 10+6+8 = 24 ohm
Potential difference = 12 V
Current through circuit = V/R = 12/24 = 0.5A
In series, current through each resistor remains same. So current through each resistor is 0.5 A
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tq
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