Question

Resistence like 30 20 40 connected in parallel then final effective resistance

Answer 1

Answer:

R=12/13

Explanation:

there are in parallel resistance

1/R = 1/30+1/20+1/40

1/R = 13/12

R=12/13

Answer 2

Answer:

$\pink{R_p = 9.24\:\Omega}$

Explanation:

Given that,

30 Ω, 20 Ω and 40 Ω resistors are connected in parallel.

$\therefore \frac{1}{R_p} = \frac{1}{30} + \frac{1}{20} + \frac{1}{40}$

$\frac{1}{R_p} = \frac{4 + 6 + 3}{120}$

$\frac{1}{R_p} = \frac{13}{120}$

$\therefore R_p = \frac{120}{13}$

$\therefore R_p = 9.24\:(approx)$

∴ The equivalent resistance is 9.24 Ω.