Resistivity of
2 metals iron & silver are l0x10^-8 ohm meter and
16 X10^-8 ohm meter respectively, & having same thickness if the
Length
of
silver rod is 20cm then the
Length of
of iron rod is
a.10cm
b. 200cm & c.32cm d] 8 cm.
Answers
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Answer:
Explanation:
R = ρ l/A
R α l
l0x10^-8 / 16 X10^-8 = Length of of iron rod/ 0.2
Length of of iron rod = 0.625*0.2
= 0.125 m
= 12.5 cm
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