resistivity of material of a wire is p. if area of cross section is doubled and length is halved, its resistivity will be
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The resistance of the wire related to length 'l' and area ‘A’ of the conductor is given by-
R=Pl/A whre P is the specific resistance of the conductor
Given l'= l/2
A'= 2A
Hence ,
R'=P(l/2)/2A
= P(l/A)*1/4
R'=1/4(R)
Hence the new resistance will be quarter the value or 1/4 of original resistance
Thank-you
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