Resistors are given as R1 = 10ohm, R2 = 20 ohm, and R3 = 30 ohm. Calculate the effective resistance when they are connected in series. Also calculate the current flowing when the combination is connected to a 6 V battery.
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Hiii..... here is ur answer
the effective resistance will be 60R since resistance are connected in series so R1+R2+R3= 10+20+30=60AND IN SERIES CONNECTION CURRENT IS CONSTANT SO I=V/R= 6/60=0.1 A is current
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the effective resistance will be 60R since resistance are connected in series so R1+R2+R3= 10+20+30=60AND IN SERIES CONNECTION CURRENT IS CONSTANT SO I=V/R= 6/60=0.1 A is current
I hope this may help you
mark me as brainlest
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