Question

resistors having resistance of 15 ohm 20 ohm and 10 ohm are connected in parallel what is the effective resistance in the circuit​

Answer 1

Answer:

$\large\boxed{\sf{R_{eff.}=\dfrac{60}{13}\;\;\Omega}}$

Explanation:

Given resistance are 15Ω , 20Ω and 10Ω.

It's said that they are connected in parallel.

Now, we know that,

When resistors are connected in parallel, effective resistance is given by the formula

$\bold \red{\dfrac{1}{R_{eff.}} = \dfrac{1}{R_{1}} + \dfrac{1}{R_{2}} + \dfrac{1}{R_{3}} + ..........}$

Therefore, we will get,

$= > \dfrac{1}{R_{eff.}} = \dfrac{1}{15} + \dfrac{1}{20} + \dfrac{1}{10} \\ \\ = > \dfrac{1}{R_{eff.}} = \frac{4 + 3 + 6}{60} \\ \\ = > \dfrac{1}{R_{eff.}} = \frac{13}{60} \\ \\ = > R_{eff.} = \frac{60}{13}$

Hence, $\bold{R_{eff.}=\dfrac{60}{13}}\Omega$