Question

reslove 3x+3/(x+1) (x+2) into partial fraction​

Answer 1

Answer:

Step-by-step explanation:

reslove 3x+3/(x+1) (x+2) into partial fraction​888+infinte=reciprocal---1-2-3-222= nothing

Answer 2

Answer:

Partial Fraction ;

3 / x² + 3x + 2

3x + 3 / ( x + 1 ) ( x + 2 )

3x + 3 = ( x + 1 ) ) x + 2 )

3x + 3 = x² + 2x + x + 2

3x + 3 = x² + 3x + 2

3x will be cancelled

3 = x² + 3x + 2

Hence ;

Partial Fraction will be

3 / x² + 3x + 2

x² + 3x + 2

x² + 1x + 2x + 2 = 0

x ( x + 1 ) + 2 ( x + 1 )

( x + 1 ) ( x + 2 )

Substitute x value in the given fraction ;

x = - 1 and -2

3x + 3 / ( x + 1 ) ( x + 2 )

3 ( -1 ) + 3 / ( -1 + 1 ) ( -1 + 2 )

-3 + 3 / 0

= 0

3x + 3 / ( x + 1 ) ( x + 2 )

3 ( -2 ) + 3 / ( -2 + 1 ) ( -2 + 2 )

-6 + 3 / 0

- 3 / 0