Question

Resolve 1-2x÷3+2x-x² into partial fractions

Answer 1

Answer:

=(2x-1)/x^2-2x-3)=(2x-1)/((x-3)(x+1)) = A/(x-3) + B/(x+1)

A(x+1) + B(x-3) = 2x -1

x(A+B) + A-3B = 2x - 1

A+B =2 and A-3B = -1

B= 3/4 and A = 5/4

Ans 5/(4(x-3)) + 3/(4(x-1)