resolve 2x+3/5(x+2)(2x+1) into partial fractions.
Answers
Step-by-step explanation:
Let I=
x
2
+2x−3
2x
2
+5x−11
=
x
2
+2x−3
2(x
2
+2x−3)+x−5
=2+
x
2
+2x−3
x−5
=2+
(x+3)(x−1)
x−5
Now
(x+3)(x−1)
x−5
=
(x−1)
A
+
(x+3)
B
⇒x−5=A(x+3)+B(x−1)
On comparing coefficients we get
1=A+B,−5=3A−B
⇒A=−1,B=2
Therefore
I=2−
x−1
1
+
x+3
2
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Answer:
Yes, I like partial fractions.
Step-by-step explanation:
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