Question

resolve 36x^4-x^2 y^2+4y^4 in factors​

Answer 1

Answer:

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Step-by-step explanation:

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try jarur krungi

Answer 2

4⋅(3x+y

2

)⋅(3x−y

2

)

See steps

Step by Step Solution:

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STEP

1

:

Equation at the end of step 1

(36 • (x2)) - 22y4

STEP

2

:

Equation at the end of step

2

:

(22•32x2) - 22y4

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

36x2 - 4y4 = 4 • (9x2 - y4)

Trying to factor as a Difference of Squares:

4.2 Factoring: 9x2 - y4

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 9 is the square of 3

Check : x2 is the square of x1

Check : y4 is the square of y2

Factorization is : (3x + y2) • (3x - y2)

Trying to factor as a Difference of Squares:

4.3 Factoring: 3x - y2

Check : 3 is not a square !!

Ruling : Binomial can not be factored as the

difference of two perfect squares

Final result :

4 • (3x + y2) • (3x - y2)

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