Question

Resolve 7x-1/6x2-5x+1 into partial fraction​

Answer 1

Answer:

(7x-1)/(6x^2-5x+1) =(7x-1)/{(2x-1)(3x-1)}

=A/(2x-1) + B/(3x-1)

={2Ax-A + 3Bx -B}/{(2x-1)(3x-1)}

={x(2A+3B)-(A+B)}/{(2x-1)(3x-1)}

2A+3B =7 and A+B =1

From these two equation you can get the values of A and B

A=5 and B= -4

Then the answer is

5/(2x-1) -4/(3x-1)

A

Answer 2

Answer:

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Step-by-step explanation:

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