Question

Resolve a vector R = 2i^-3 j^ into two perpendicular components such that one of its Commponents makes and angle of 45° with (+ x-axis)​

Answer 1

Answer

Explanation:

• This is the resolution

Answer 2

Answer:

The components are $\sqrt{2}$ and $-\frac{3}{\sqrt{2} }$.

Explanation:

We are given with vector $R = 2i^-3 j^$

We need to resolve it in to two perpendicular components such that one of its components makes and angle of$45$ degrees with (+ $x$-axis)​.

As per the given information,

The magnitude in positive $x$ axis is $2$ and in negative $y$ axis is $3$.

If it makes angle of $45$ degrees with $x$ axis,

$r_{x} =2cos45=2*\frac{1}{\sqrt{2} } =\sqrt{2}$

and

$r_{y} =-3sin45=-3*\frac{1}{\sqrt{2} } =-\frac{3}{\sqrt{2} }$

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