Question

Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.​

Answer 1

ʜᴏʟᴀ ᴍᴀᴛᴇ !

$\: \: \: \: \: \: \: \: \: \: \:$

⭐ᴀɴsᴡᴇʀ⭐

Let the force 10N makes an angle θ with the inclined line

parallel component = 10×sinθ N ; perpendicular component = 10×cosθ N

Answer 2

Answer:

hy❤

Explanation:

Let the force 10N makes an angle θ with the inclined line

Parallel component = 10×sinθ N ;

Perpendicular component = 10×cosθ N

hope this helps

have a NYC day❤

keep smiling☺☺✌✌

Candy❤