Question

Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal.​

Answer 1

Answer:

Let the force 10N makes an angle θ with the inclined line

• parallel component = 10×sinθ N ; perpendicular component = 10×cosθ N

Answer 2

HOPE IT HELPS YOU

.

.

Mark me as BRAINLIST please