Question

resolve in factors a²-2ab+b²-c² answer with explanation​

Answer 1

$(a {}^{2} - 2ab + b {}^{2} ) - c {}^{2} = (a - b) {}^{2} - c {}^{2} = take \: the \: formula \: a {}^{2} - b{}^{2} where \: a= ab \: and \: b = c \: then \: (a - b) {}^{2} - c {}^{2} = (a - b) + c)(a - b) - c)$

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Answer 2

Answer:

Resolving into factors, we get =(a-b+c) (a-b-c).

Step-by-step explanation:

Given expression, a²-2ab+b²-c²

=(a²)-2(a)(b)+(b)²-c²

=(a-b)²-c²

=(a-b)²-(c)²

={(a-b)+c} {(a-b)-c} [∵we know,  x²-y²= (x+y)(x-y)]

=(a-b+c) (a-b-c)

Resolving into factors, we get =(a-b+c) (a-b-c).