Question

resolve in factors . in detail ​

Answer 1

Answer:

Hope this helps!!!!

Step-by-step explanation:

x²+x-12=0

x²+4x-3x-12=0

x(x+4)-3(x+4)=0

(x+4)(x-3)=0

x+4=0 and x-3=0

x= -4 and x=3.

x²-7x+12=0

x²-3x-4x+12=0

x(x-3)-4(x-3)=0

(x-3)(x-4)=0

x-3=0 and x-4=0

x=3 and x=4.

x²-8x+15=0

x²-5x-3x+15=0

x(x-5)-3(x-5)=0

(x-5)(x-3)=0

x-5=0 and x-3=0

x=5 and x=3.

x²-9x+18=0

x²-3x-6x+18=0

x(x-3)-6(x-3)=0

(x-3)(x-6)=0

x-3=0 and x-6=0

x=3 and x=6.

x²+4x-21=0

x²+7x-3x-21=0

x(x-7)-3(x-7)=0

(x-7)(x-3)=0

x-7=0 and x-3=0

x=7 and x=3.