Question

Resolve in to Partial fractions
x²+x+1/
(X-1 (x-2)(x-3)​

Answer 1

Answer:

ANSWER. IS. 0

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Answer 2

Answer:

$The expansion for x2(x−1)3 is given by</p><p></p><p>x2(x−1)3=A(x−1)+B(x−1)2+C(x−1)3</p><p></p><p>reducing the right member to common denominator we have</p><p></p><p>x2(x−1)3=A(x−1)2+B(x−1)+C(x−1)3</p><p></p><p>Equating the numerators we have</p><p></p><p>x2=Ax2+(B−2A)x+A−B+C</p><p></p><p>giving the following conditions</p><p></p><p>⎧⎪⎨⎪⎩A=1B−2A=0A−B+C=0</p><p></p><p>solving for A,B,C we get</p><p></p><p>x2(x−1)3=1(x−1)+2(x−1)2+1(x−1)3</p><p></p><p></p><p></p><p>$

Step-by-step explanation:

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