resolve into denominator x/(x+3)(x-4)
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Answer:
Resolve into denominator
(x+1)
2
(x−3)
x
4
+3x
3
−3x
2
+10
=x−2−
(x+1)
2
(x−3)
7x−4
Now assume,
(x+1)
2
(x−3)
7x−4
=
(x+1)
A
+
(x+1)
2
B
+
(x−3)
C
After Simplifying this, we get
A(x+1)(x−3)+B(x−3)+C(x+1)
2
=7x−4
On solving for A,B and C, we get
A=
16
−17
,B=
4
11
,C=
16
17
∴
(x+1)
2
(x−3)
x
4
+3x
3
−3x
2
+10
=x−2−
16(x+1)
−17
+
4(x+1)
2
11
+
16(x−3)
17
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