Question

resolve into factor​

Answer 1

not much time to answers your question

Answer 2

Answer:

Given that, a/b + b/a = 1

Taking LCM of a and b, which is equal to ab.

a/b + b/a = (a² + b²)/ab = 1

or a² + b² = ab

Now,

a³+ b³ = ( a + b ) ( a² - ab - b² )

[ab = a² + b²]

=> a³+ b³ = ( a + b ) [ a² - (a² + b²) - b² ]

= ( a + b ) ( a² - a² - b² - b² )

= ( a + b ) ( -2 b² )

Therefore, a³+ b³ = ( a + b ) ( -2 b² )