Math, asked by aditimahat2, 2 months ago

Resolve into factors :
1) 4x² + 12x + 5

2) 5x² + 13x - 6
please help me out

Answers

Answered by bagkakali
0

Answer:

1) 4x^2+12x+5

=4x^2+10x+2x+5

=2x(2x+5)+1(2x+5)

=(2x+5)(2x+1)

2) 5x^2+13x-6

=5x^2+15x-2x-6

=5x(x+3)-2(x+3)

=(x+3)(5x-2)

Answered by misscutie94
1

Answer:

Question :-

1) 4x² + 12x + 5

Solution :-

➪ 4x² + 12x + 5 = 0

➭ 4x² + (10 + 2)x + 5 = 0

➭ 4x² + 10x + 2x + 5 = 0

➭ 2x(2x + 5) + 1(2x + 5) = 0

➭ (2x + 5) (2x + 1) = 0

➭ (2x + 5) = 0

➭ 2x + 5 = 0

➭ 2x = 5

➭ x = 5/2

Either,

➭ (2x + 1) = 0

➭ 2x + 1 = 0

➭ 2x = - 1

➭ x = - 1/2

∴ The value of x is 5/2, - 1/2

Question :-

2) 5x² + 13x - 6

Solution :-

➪ 5x² + 13x - 6 = 0

➭ 5x² + (15 - 2)x - 6 = 0

➭ 5x² + 15x - 2x - 6 = 0

➭ 5x(x + 3) - 2(x + 3) = 0

➭ (x + 3) (x - 2) = 0

➭ (x + 3) = 0

➭ x + 3 = 0

➭ x = - 3

Either,

➭ (x - 2) = 0

➭ x - 2 = 0

➭ x = 2

∴ The value of x is - 3, 2

Similar questions