resolve into factors
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(a-2b)²-4a+8b
(a-2b)²-4(a-2b)
taking (a-2b) common , we get ,
(a-2b)[(a-2b)-4]
(a-2b)(a-2b-4)
hope this helps
(a-2b)²-4(a-2b)
taking (a-2b) common , we get ,
(a-2b)[(a-2b)-4]
(a-2b)(a-2b-4)
hope this helps
RJalam:
is it correct
yes I'm quite sure
if i do with (a-b)whole square then will it be
no i don't think so ur answer will come
ok
this is the right answer..... friend
okay
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