Math, asked by Tanay2909, 1 year ago

Resolve into factors
2. A^4b^4......​

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Answers

Answered by Anonymous
0

a4*b^4-c^4

((ab)^2+c^2)(ab+1)(ab-1)

hope it may help yoi


Tanay2909: How to solve this
Answered by apurvaa200297
1

(ab) ^{4}  - c ^{4}  = (a ^{2} b ^{2} ) -  \: (c ^{2} ) ^{2}

x ^{2}  - y ^{2}  = (x + y)(x - y)

so  \: t he \: above \: equation \: becomes

(ab + c)(ab - c \: )


apurvaa200297: see 2^3=8
apurvaa200297: and multiples of 2 are of the form 2x like 4=2×2 and 8=2×4
apurvaa200297: so (2x)^3=(2^3)(x^3)=8x^3
apurvaa200297: it is always a multiple of 8
apurvaa200297: sorry
apurvaa200297: it was for somebody else
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