Question

resolve into factors: 4a2 - 4ab - 2bc - c2​

Answer 1

Solution

4a2+b2+c2−4ab+2bc−4ca

 We know that

x2+y2+z2+2xy+2yz+2xz=(x+y+z)2

Here,

x=2a

y=−b

and

z=−c

4a2+b2+c2−4ab+2bc−4ca

=

(2a)2+(−b)2−(c)2−2(2a)(−b)+2(−b)(−c)+2(2a)(−b)

(2a−b−c)2=(2a−b−c)(2a−b−c)

Answer 2

Answer:

(2a + c)(2a - c - 2b)

Step-by-step explanation:

4a² - 4ab - 2bc - c²

4a² - c² - 4ab - 2bc (rearranging)

(2a + c)(2a - c) -2b(2a + c)

Taking 2a + c as common:

(2a + c)(2a - c - 2b)

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