Question

Resolve into factors 4a² - (b - 1)²​

Answer 1

Answer:($(2a+b-1)(2a-b+1)$

Step-by-step explanation:

$4a^2-(b-1)^2=(2a)^2-((b-1)^2$

using identity: $a^2-b^2=(a+b)(a-b)$

$(2a+(b-1))(2a-(b-1))$

$(2a+b-1)(2a-b+1)$

Answer 2

Answer:

4a² - (b - 1)² = (2a - b + 1)(2a + b - 1)

Step-by-step explanation:

We have,

4a² - (b - 1)²

We must know that,

It is of the form x² - y²

We know that,

x² - y² = (x - y)(x + y)

If x² = 4a²

x = √4a²

x = 2a

If y² = (b - 1)²

y = √(b - 1)²

y = b - 1

Then, factorising,

4a² - (b - 1)² = [2a - (b - 1)][2a + (b - 1)]

= (2a - b + 1)(2a + b - 1)

Hence,

4a² - (b - 1)² = (2a - b + 1)(2a + b - 1)

Hope it helped you and believing you understood it...All the best