resolve into factors 4y^2- 2y+1/4
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Answer:
16y²-8y+1=0
16y²-4y-4y+1=0
4y(4y-1)-1(4y-1)=0
y=1/4 OK friend
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4y^2-y-y+1/4
y(4y-1)-1/4(4y-1)
(y-1)(4y-1)
Therefore,
Y=1 and Y=1/4
Pls mark me as brainiest!!!
y(4y-1)-1/4(4y-1)
(y-1)(4y-1)
Therefore,
Y=1 and Y=1/4
Pls mark me as brainiest!!!
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