Math, asked by masterhassan386, 2 months ago

resolve into factors 6a^2 +11a _10​

Answers

Answered by 3kvibxss
0

Answer:

 (2a - 5) • (3a + 2)

Step-by-step explanation:

2.1     Factoring  6a2-11a-10  

The first term is,  6a2  its coefficient is  6 .

The middle term is,  -11a  its coefficient is  -11 .

The last term, "the constant", is  -10  

Step-1 : Multiply the coefficient of the first term by the constant   6 • -10 = -60  

Step-2 : Find two factors of  -60  whose sum equals the coefficient of the middle term, which is   -11 .

     -60    +    1    =    -59  

     -30    +    2    =    -28  

     -20    +    3    =    -17  

     -15    +    4    =    -11    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -15  and  4  

                    6a2 - 15a + 4a - 10

Step-4 : Add up the first 2 terms, pulling out like factors :

                   3a • (2a-5)

             Add up the last 2 terms, pulling out common factors :

                   2 • (2a-5)

Step-5 : Add up the four terms of step 4 :

                   (3a+2)  •  (2a-5)

            Which is the desired factorization

Answered by cbse5005
0

Answer:

Factors of this are 6a, a, 11a, a, a, a, a, a, a, a, a, a, a

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