Question

resolve into factors :- 8a³ - 1​

Answer 1

Answer:

Step-by-step explanation:

To factorise,

1 - 8 {a}^{3}1−8a

3

We can further simplify this as,

= {1}^{3} - 8 {a}^{3}=1

3

−8a

3

Or, we can simplify,

= {(1)}^{3} - {(2a)}^{3}=(1)

3

−(2a)

3

Now, we know that,

{x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} )x

3

−y

3

=(x−y)(x

2

+xy+y

2

)

Therefore, we will get,

= (1 - 2a)( {(1)}^{2} + (1)(2a) + {(2a)}^{2} )=(1−2a)((1)

2

+(1)(2a)+(2a)

2

)

Further simplify, we will get,

= (1 - 2a)(1 + 2a + 4 {a}^{2} )=(1−2a)(1+2a+4a

2

)

Hence, the factors are :-

(1 - 2a)(1 + 2a + 4 {a}^{2} )(1−2a)(1+2a+4a

2

)

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

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