Question

resolve into factors
a^2-b^2+4bc-4c^2​

Answer 1

Step-by-step explanation:

Given : a2−b2−4ac+4c2

We can write it as 

a2−b2−4ac+4c2=a2−4ac+4c2−b2

So we get 

a2−b2−4ac+4c2=a2−2×a×2x+2c2−b2

a2−b2−4ac+4c2=(a−2c)2−b2

Based on the equation a2−b2=(a+b)(a−b)

We get,

a2−b2−4ac+4c2=(a−2c+b)(a−2c−b)