Question

resolve into factors: a2 - 4 (b2 - a - 1)​

Answer 1

Answer:

a^2-4(b^2-a-1)

=a^2-4b^2+4a+4

=a^2+4a+4-4b^2

=(a)^2+2.a.2+(2)^2-(2b)^2

=(a+2)^2-(2b)^2

=(a+2+2b)(a+2-2b)

=(a+2b+2)(a-2b+2)