Math, asked by nitinverma8550, 6 hours ago

Resolve into factors and choose the correct answer : a3+3a2b+3ab2+2b3

Answers

Answered by deshrajguleria11
0

Answer:

Factorise the expression a^3 -3a^2b +3ab^2+2b^3a

3

−3a

2

b+3ab

2

+2b

3

TO FIND :

The factors of the given expression by using factorisation method.

SOLUTION :

Given expression is a^3 -3a^2b +3ab^2+2b^3a

3

−3a

2

b+3ab

2

+2b

3

Now factorise the given expression a^3 -3a^2b +3ab^2+2b^3a

3

−3a

2

b+3ab

2

+2b

3

That is solving the expression a^3 -3a^2b +3ab^2+2b^3a

3

−3a

2

b+3ab

2

+2b

3

as below:

a^3 -3a^2b +3ab^2+2b^3a

3

−3a

2

b+3ab

2

+2b

3

Rewritting the above expression for our convenient to solve it we get,

=a^3 -3a^2b +3ab^2+3b^3-b^3=a

3

−3a

2

b+3ab

2

+3b

3

−b

3

=(a^3 -3a^2b +3ab^2-b^3)+3b^3=(a

3

−3a

2

b+3ab

2

−b

3

)+3b

3

By using the algebraic identity :

(a-b)^3=a^3-3a^2b+3ab^2-b^3(a−b)

3

=a

3

−3a

2

b+3ab

2

−b

3

=(a-b)^3+3b^3=(a−b)

3

+3b

3

∴ a^3 -3a^2b +3ab^2+2b^3=(a-b)^3+3b^3a

3

−3a

2

b+3ab

2

+2b

3

=(a−b)

3

+3b

3

∴ the given expression a^3 -3a^2b +3ab^2+2b^3a

3

−3a

2

b+3ab

2

+2b

3

is factorised into (a-b)^3+3b^3(a−b)

3

+3b

3

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