Question

Resolve into factors: (m+3n)²+4m+12n

✌️ Khushi ✌️​

Answer 1

Explanation:

$\mathsf{(m+3n)^2+4m+12n}$

$\mathsf{=(m+3n)^2+4(m+3n)}$ [bringing out 4 as the common factor]

$\mathsf{=(m+3n)[(m+3n)+4]}$ [bringing out (m + 3n) to be the common factor]

$\mathsf{=(m+3n)(m+3n+4)}$ [opening the brackets]

Answer: (m + 3n)(m + 3n + 4)

I hope this helps. :D

Answer 2

apke itne question khali hai pta hu nhi chalta ki kaunsa khali hai.

itz Arpan here✌✌ the friend maker