Question

Resolve into factors of 16x4 -(z-x)4

Answer 1

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Here is your answer
$16 {x}^{4} - (z - x) {}^{4} \\ = (4 {x}^{2} ) {}^{2} - ((z - x) {}^{2} ) {}^{2} \\ = (4 {x}^{2} - (z - x) {}^{2})(4 {x}^{2} + (z - x) {}^{2}) \\ = ( (2x) {}^{2} - ( z - x) {}^{2})(4 {x}^{2} + z {}^{2} + {x}^{2} - 2zx) \\ = ((2 x + (z - x))((2x - (z - x))(5 {x}^{2} + {z}^{2} - 2zx) \\ = (2x + z - x)(2x - z + x)(5 {x}^{2} + {z}^{2} - 2zx) \\ = (x + z)(3x - z)(5 {x}^{2} + {z}^{2} - 2zx)$

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Answer 2

Answer:

16x ^ 4 - (z - x) ^ 4 factorize the fallowing