Question

Resolve into factors p2+31pq+108q2​

Answer 1

Answer:

To resolve it into factors we first resolve 108

108=2×2×3×3×3

Given, x2 + (m + n)x + mn=(x + m)(x + n) … (2)

Comparing 1 and 2

m + n =31

mn =108

∴ (1) can be written as

p2 + 27pq + 4pq + 108q2

= (p + 27q)( p + 4q)

∴ The resolved factors are (p + 27q)( p + 4q)

Step-by-step explanation:

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Answer 2

Answer:

To resolve it into factors we first resolve 108

108=2×2×3×3×3

Given, x2 + (m + n)x + mn=(x + m)(x + n) … (2)

Comparing 1 and 2

m + n =31

mn =108

∴ (1) can be written as

p2 + 27pq + 4pq + 108q2

= (p + 27q)( p + 4q)

∴ The resolved factors are (p + 27q)( p + 4q)

Step-by-step explanation:

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