Question

resolve into factors Question: 27(a+b)³ + 1 remember that answer should be for class 8th stage and formula : a³+b³ = (a+b) (a²+ab+b²) this may use different type of bracket and the thing i knew is the answer will be after long solution​

Answer 1

Answer:

(a−b)3=a3−3a2b+3ab2−b3(a−b)3=a3−3a2b+3ab2−b3

Take other elements to the LHS of the equation and we get,

(a−b)3+3a2b−3ab2=a3−b3(a−b)3+3a2b−3ab2=a3−b3

i.e. a3−b3=(a−b)3+3a2b−3ab2a3−b3=(a−b)3+3a2b−3ab2

Which can further be simplified as

a3−b3=(a−b)3+3ab(a−b)a3−b3=(a−b)3+3ab(a−b)

a3−b3=(a−b)[(a−b)2+3ab]a3−b3=(a−b)[(a−b)2+3ab]

a3−b3=(a−b)(a2–2ab+b2+3ab)a3−b3=(a−b)(a2–2ab+b2+3ab)

a3−b3=(a−b)(a2+ab+b2)a3−b3=(a−b)(a2+ab+b2)

Step-by-step explanation:

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