Question

resolve into factors
$12 {x}^{3} y + 20 {x}^{4} {y}^{3}$
with step by step explaination please​

Answer 1

Answer:

$\:Required\:Factors:\:\bold{\boxed{4x^{3}y(3+5xy^{2})}}$

Step-by-step explanation:

$12x^{3}y+20x^{4}y^{3}\\Taking\:4x^{3}y\:from\:both\:the\:terms,\:we\:get,\\ =4x^{3}y(3+5xy^{2})$

$Hence,\:Required\:Factors:\:\bold{\boxed{4x^{3}y(3+5xy^{2})}}$

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Answer 2

Answer:

$\implies \sf 4x^3y(5xy^2+3)$

Step-by-step explanation:

$\implies \sf 12x^3y + 20x^4y^3$

$\implies \sf 20x^4y^3+12x^3y$

Final Answer

$\implies \sf 4x^3y(5xy^2+3)$

What is factorisation?

• Factorisation is a method to find factors of the given polynomial.

• They are generally written as product of other factors.

• To factories a quadratic polynomial splitting the middle term is widely used.

• While identities, and simplification can also be used to factories.