Question

resolve into factors
$8(x + y) {}^{3} - z {}^{2}$


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Answer 1

Answer:

Factorisation is the opposite process of expanding brackets. For example, expanding brackets would require \(2(x + 1)\) to be written as \(2x + 2\). Factorisation would be to start with \(2x + 2\) and end up with \(2(x + 1)\).

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The two expressions \(2(x + 1)\) and \(2x+2\) are equivalent; they have the same value for all values of \(x\).

In previous grades, we factorised by taking out a common factor and using difference of squares.