resolve into factors
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Answered by
5
Now,
m²n² - 6mnp + 9p²
= m²n² - (3 + 3)mnp + 9p²
= m²n² - 3mnp - 3mnp + 9p²
= mn (mn - 3p) - 3p (mn - 3p)
= (mn - 3p) (mn - 3p),
which is the required factorization.
Here, (mn - 3p) and (mn - 3p) are the two factors of the given polynomial.
#
Answered by
7
(mn - 3p)²
“you can do it in two methods,”
✔The first one,
a² - 2ab + b² = (a - b)²
♦ m²n² - 6mnp + 9p²
= m²n² - 6mnp + 3²p²
= (mn)² - 2(mn) (3p) + (3p)²
= (mn - 3p)²
“the answer came as (mn - 3p)² because,
“according to the formula,”
a² - 2ab + b²
= (mn)² - 2(mn) (3p) + (3p)²
is equal to
(a - b)²
= (mn - 3p)²
✔The second one,
“by spliting the middle term,”
♦ m²n² - 6mnp + 9p²
[here, we can split the middle term “6mnp” by 3+3]
= m²n² - (3+3)mnp + 9p²
= m²n² - 3mnp - 3mnp + 9p²
[Now, here we need to find common factors between the first & the last two equations]
= mn(mn - 3p) - 3p(mn - 3p)
= (mn - 3p) (mn - 3p)
= (mn - 3p)²
You can use any of these two methods, whichever you feel comfortable.
_______________________
_______________________
#be brainly
“you can do it in two methods,”
✔The first one,
a² - 2ab + b² = (a - b)²
♦ m²n² - 6mnp + 9p²
= m²n² - 6mnp + 3²p²
= (mn)² - 2(mn) (3p) + (3p)²
= (mn - 3p)²
“the answer came as (mn - 3p)² because,
“according to the formula,”
a² - 2ab + b²
= (mn)² - 2(mn) (3p) + (3p)²
is equal to
(a - b)²
= (mn - 3p)²
✔The second one,
“by spliting the middle term,”
♦ m²n² - 6mnp + 9p²
[here, we can split the middle term “6mnp” by 3+3]
= m²n² - (3+3)mnp + 9p²
= m²n² - 3mnp - 3mnp + 9p²
[Now, here we need to find common factors between the first & the last two equations]
= mn(mn - 3p) - 3p(mn - 3p)
= (mn - 3p) (mn - 3p)
= (mn - 3p)²
You can use any of these two methods, whichever you feel comfortable.
_______________________
_______________________
#be brainly
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