Math, asked by milli77, 1 year ago

resolve into factors
 {m}^{2}  {n}^{2}  - 6mnp + 9 {p}^{2}

Answers

Answered by MarkAsBrainliest
5
\textbf{Answer :}

Now,

m²n² - 6mnp + 9p²

= m²n² - (3 + 3)mnp + 9p²

= m²n² - 3mnp - 3mnp + 9p²

= mn (mn - 3p) - 3p (mn - 3p)

= (mn - 3p) (mn - 3p),

which is the required factorization.

Here, (mn - 3p) and (mn - 3p) are the two factors of the given polynomial.

#\textbf{MarkAsBrainliest}
Answered by BlackVenom05
7
 \textbf{Answer :} (mn - 3p)²

 \textbf{Solution :}

“you can do it in two methods,”

✔The first one,

a² - 2ab + b² = (a - b)²

♦ m²n² - 6mnp + 9p²

= m²n² - 6mnp + 3²p²

= (mn)² - 2(mn) (3p) + (3p)²

= (mn - 3p)²

“the answer came as (mn - 3p)² because,

“according to the formula,”

a² - 2ab + b²

= (mn)² - 2(mn) (3p) + (3p)²

is equal to

(a - b)²

= (mn - 3p)²

✔The second one,

“by spliting the middle term,”

♦ m²n² - 6mnp + 9p²

[here, we can split the middle term “6mnp” by 3+3]

 \textbf{Kindly refer to the attachment}

= m²n² - (3+3)mnp + 9p²

= m²n² - 3mnp - 3mnp + 9p²

[Now, here we need to find common factors between the first & the last two equations]

= mn(mn - 3p) - 3p(mn - 3p)

= (mn - 3p) (mn - 3p)

= (mn - 3p)²

You can use any of these two methods, whichever you feel comfortable.

_______________________

 \textbf{Hope it helps you}

 \textbf{Have a great day ahead}
_______________________

#be brainly
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BlackVenom05: *^O^*
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