Math, asked by alokarjun993, 1 month ago

Resolve into factors
( {x}^{2} - 2xy) - ( {z}^{2} - 2yz)

Answers

Answered by piwaniyasunitav85
0

= x² - 2xy - z² +2yz

= x² - z² +2yz - 2xy

= (x+z)(x-z) + 2y(z-x)

=(x-z)[x+z-2y]

HOPE IT WILL BE HELPFUL

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